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    Biology (0610)

    May/June 2025 Paper 31 Worked Answers (IGCSE Biology 0610 Core)

    39 questions · 80 marks · 75 minutes

    Question papers and mark schemes are copyright Cambridge International. We do not reproduce them: the worked answers here are written by The Practice Book. Have the paper open alongside. Get the official paper from Cambridge

    Worked answers for 34 questions
    1. Question 1(b)(i)

      1 marksFunction of the nucleus
      Step 1: The nucleus holds the chromosomes, which carry the genetic material (DNA). Step 2: Using these instructions, the nucleus controls the activities of the cell. Step 3: Releasing energy is the job of mitochondria, controlling entry and exit is the membrane, and photosynthesis happens in chloroplasts.
      Method:
      Recall that the nucleus stores DNA and directs the cell.
      Examiner tips
      • Nucleus = genetic material + control centre of the cell.
    2. Question 1(b)(ii)

      2 marksComponents present in all cells
      Step 1: Every cell, animal or plant, is surrounded by a cell membrane and filled with cytoplasm. Step 2: Ribosomes are also found in all cells, so cell membrane and cytoplasm are a correct pair. Step 3: Cell walls, chloroplasts and large permanent vacuoles are found only in plant cells, not in all cells.
      Method:
      Pick structures common to both animal and plant cells.
      Examiner tips
      • Cell membrane, cytoplasm and ribosomes are in every cell; wall, chloroplasts and large vacuole are plant-only.
    3. Question 1(c)

      2 marksAdaptation of a root hair cell
      Step 1: The long projection gives the root hair cell a large surface area. Step 2: This large surface area, together with a large permanent vacuole, speeds up the uptake of water and mineral ions from the soil. Step 3: Chloroplasts are for photosynthesis, a waxy layer reduces water loss in leaves, and cilia move mucus, so none of these fit a root hair cell.
      Method:
      Link the shape of the cell to faster absorption of water and minerals.
      Examiner tips
      • Root hair cell = large surface area + large vacuole for absorbing water and mineral ions.
    4. Step 1: Actual size = image size ÷ magnification, so both the image size and the magnification are needed. Step 2: Measuring the image and knowing the magnification lets you calculate the real length. Step 3: The number of cells, the stain colour and the cell width do not appear in this calculation.
      Method:
      Recall the magnification equation and pick the two quantities it uses.
      Examiner tips
      • Actual size = image size ÷ magnification, so you need image size and magnification.
    5. Step 1: The bubble count rises (5→21) as carbon dioxide increases, and carbon dioxide is a raw material used in photosynthesis. Step 2: The count is 21 at both 0.4 and 0.5, so it stays the same between 0.4 and 0.5 arbitrary units, and the gas released as bubbles is oxygen. Step 3: Keeping the lamp at a fixed distance keeps the light intensity constant, so the correct set is increases; raw; 0.4 and 0.5; oxygen; intensity.
      Method:
      Read the trend from the data, then recall the raw materials and products of photosynthesis.
      Examiner tips
      • Carbon dioxide is a raw material; oxygen is the product; lamp distance controls light intensity.
    6. Question 2(b)

      4 marksImportance of chlorophyll
      Step 1: The green pigment is chlorophyll, found in the chloroplasts. Step 2: Chlorophyll absorbs light energy and transfers it to chemical reactions. Step 3: This energy is used to make carbohydrates such as glucose in photosynthesis, so chlorophyll is essential for the plant’s nutrition.
      Method:
      Name the pigment, then state how it captures light energy for photosynthesis.
      Examiner tips
      • Chlorophyll absorbs light energy and transfers it to make glucose.
    7. Step 1: Respiration breaks down glucose to release energy and produces carbon dioxide as a waste gas. Step 2: Plants respire all the time, so respiration is the process that produces carbon dioxide. Step 3: Photosynthesis uses carbon dioxide, while transpiration is water loss and translocation moves sugars, so none of these produce carbon dioxide.
      Method:
      Recall which process releases carbon dioxide as a waste gas.
      Examiner tips
      • Respiration produces carbon dioxide; photosynthesis uses it.
    8. Question 3(a)

      4 marksOrgans of the digestive system
      Step 1: Physical digestion (churning) occurs in the stomach, which also releases hydrochloric acid. Step 2: The pancreas secretes the enzymes protease and amylase into the small intestine. Step 3: The pancreas also secretes the hormone insulin, so the order is stomach; stomach; pancreas; pancreas.
      Method:
      Match each function to the organ that performs it in the digestive system.
      Examiner tips
      • Stomach: churning + acid. Pancreas: protease, amylase, lipase + insulin.
    9. Question 3(b)

      2 marksFunctions of hydrochloric acid
      Step 1: Hydrochloric acid kills many of the microorganisms taken in with food. Step 2: It also makes the stomach contents acidic, giving the optimum (low) pH for the protease enzymes in the stomach to work. Step 3: Bile emulsifies fats, the small intestine absorbs food, and blood carries gases, so these are not functions of stomach acid.
      Method:
      Recall the two roles of stomach acid and reject jobs done by bile or blood.
      Examiner tips
      • Stomach acid: kills microorganisms + gives the optimum pH for protease.
    10. Question 3(c)

      3 marksImportance of protease
      Step 1: Protease is an enzyme that digests large protein molecules. Step 2: It breaks proteins down into amino acids, which are small and soluble. Step 3: Being small and soluble, the amino acids can be absorbed into the blood, so protease is important for making proteins absorbable.
      Method:
      State that protease is an enzyme, name its product, and explain why that helps absorption.
      Examiner tips
      • Protease digests protein into amino acids that are small and soluble enough to absorb.
    11. Step 1: Iodine solution turns blue-black when starch is present and stays yellow-brown when it is not. Step 2: Tube X has starch only, so it turns blue-black. Step 3: In tube Y the amylase digests the starch into sugars, so no starch remains and the iodine stays yellow-brown.
      Method:
      Decide which tube still has starch, then apply the iodine colour change.
      Examiner tips
      • Starch present → blue-black; starch digested → yellow-brown.
    12. Question 3(d)(ii)

      1 marksReason for different iodine colours
      Step 1: Iodine only turns blue-black if starch is present. Step 2: In Y the amylase has broken the starch down into sugars, so no starch is left and the colour is different. Step 3: In X there is no amylase, so the starch remains and gives the blue-black colour, which is why the two tubes differ.
      Method:
      Explain the colour difference by where the starch has been digested.
      Examiner tips
      • Different colours = starch digested in one tube but not the other.
    13. Question 4(a)

      3 marksDefinition of sense organs
      Step 1: Sense organs are made of receptor cells that detect changes. Step 2: The changes they detect are called stimuli. Step 3: Common stimuli include light, sound, touch, temperature and chemicals, so the missing stimulus in the list is sound, giving receptor; stimuli; sound.
      Method:
      Recall the definition of a sense organ and the named list of stimuli.
      Examiner tips
      • Receptor cells detect stimuli such as light, sound, touch, temperature and chemicals.
    14. Question 4(b)

      2 marksPupil response to dim light
      Step 1: In dim light the circular muscles of the iris relax and the radial muscles contract, so the pupil widens (its diameter increases). Step 2: A wider pupil lets more light into the eye. Step 3: This extra light helps the person to see in the dim conditions, so the pupil widens to allow more light in.
      Method:
      State how the pupil changes in dim light, then explain why more light is needed.
      Examiner tips
      • Dim light → pupil widens → more light enters. Bright light → pupil narrows.
    15. Question 4(c)(i)

      1 marksPosition of the blind spot
      Step 1: The blind spot is the part of the retina that contains no light receptor cells. Step 2: This is the point where the optic nerve leaves the back of the eye. Step 3: The cornea, iris and lens are at the front of the eye and are not the blind spot, which is at the back where the nerve exits.
      Method:
      Locate the blind spot at the exit point of the optic nerve from the retina.
      Examiner tips
      • Blind spot = where the optic nerve leaves the retina, so no receptors are present.
    16. Step 1: The biggest percentage change is +7.55 at 0.10 mol per dm³, so that cylinder showed the largest change. Step 2: At 1.00 mol per dm³ the mass falls (−5.28), because water leaves the cylinder by osmosis into the more concentrated solution. Step 3: All the mass changes happen because water crosses the partially permeable cell membranes, so those three conclusions are correct.
      Method:
      Compare the percentage values and apply the idea that water moves by osmosis.
      Examiner tips
      • Osmosis moves water across the membrane; the largest percentage value marks the largest change.
    17. Question 5(a)(ii)

      1 marksProcess causing mass change
      Step 1: Water moves across a partially permeable membrane from a dilute to a more concentrated solution. Step 2: This movement of water is called osmosis. Step 3: Active transport moves ions against a gradient using energy, respiration releases energy, and transpiration is water loss from leaves, so the process here is osmosis.
      Method:
      Name the process by which water crosses the cell membrane.
      Examiner tips
      • Osmosis = movement of water across a partially permeable membrane.
    18. Question 5(a)(iii)

      2 marksFactors affecting rate of mass change
      Step 1: Higher temperature gives water molecules more energy, speeding up osmosis. Step 2: A larger surface area of the cylinders lets water cross the membranes faster. Step 3: Colour, time of day, beaker mass and other irrelevant factors do not affect the rate, so temperature and surface area are the influencing factors.
      Method:
      Pick the variables that change how fast water crosses the membranes.
      Examiner tips
      • Rate of osmosis rises with higher temperature and larger surface area.
    19. Step 1: As water enters, the plant cell swells and presses outwards on its surroundings. Step 2: The strong cellulose cell wall is rigid and resists this pressure, stopping the cell from bursting. Step 3: The membrane, cytoplasm and nucleus cannot provide this support, so it is the cell wall that prevents bursting.
      Method:
      Identify the rigid plant-cell structure that resists the pressure of incoming water.
      Examiner tips
      • The cellulose cell wall is rigid and prevents a plant cell from bursting.
    20. Question 5(c)(i)

      2 marksUses of water in the body
      Step 1: Water dissolves many substances, so it acts as a solvent in the body. Step 2: Blood, which is mostly water, transports dissolved substances around the body, so water is used for transport. Step 3: Enzymes are proteins, genetic material is DNA, and phagocytosis is carried out by white blood cells, so those are not uses of water.
      Method:
      Choose the two roles that describe water dissolving and carrying substances.
      Examiner tips
      • Water acts as a solvent and as the transport medium of the blood.
    21. Question 5(c)(ii)

      2 marksComponents of a balanced diet
      Step 1: A balanced diet provides carbohydrates, proteins, fats, vitamins, minerals, fibre and water. Step 2: Carbohydrate and protein are two of these named components. Step 3: Oxygen and carbon dioxide are gases, urea and bile are body wastes/secretions, and haemoglobin and insulin are made in the body, so none of these are dietary components.
      Method:
      Recall the seven components of a balanced diet and pick two.
      Examiner tips
      • Balanced diet = carbohydrate, protein, fat, vitamins, minerals, fibre and water.
    22. Question 6(a)(i)

      1 marksIdentifying types of blood vessel
      Step 1: Arteries have thick muscular walls and a narrow lumen to withstand high pressure, so vessel Z is an artery. Step 2: Veins have thinner walls and a large lumen to carry blood at low pressure, so vessel X is a vein. Step 3: Capillaries have very thin walls (one cell thick) and a very narrow lumen, so vessel Y is a capillary.
      Method:
      Match each set of wall and lumen features to the correct vessel type.
      Examiner tips
      • Artery: thick wall, narrow lumen. Vein: thin wall, large lumen. Capillary: one cell thick.
    23. Question 6(a)(ii)

      2 marksValves in veins
      Step 1: Veins contain valves that arteries and capillaries do not have. Step 2: Because blood in veins is at low pressure, these valves stop the blood flowing backwards. Step 3: They ensure a one-way flow of blood back to the heart; valves do not pump, and cilia and villi are found elsewhere.
      Method:
      Name the structure unique to veins and state how it controls blood flow.
      Examiner tips
      • Valves in veins ensure one-way flow of blood back to the heart.
    24. Step 1: The kidneys filter the blood and remove urea, a waste made in the liver. Step 2: They also remove excess water and excess mineral ions to keep the body balanced. Step 3: Glucose and amino acids are reabsorbed, gases are exchanged in the lungs, and cells and proteins are too large to be filtered, so the kidneys excrete urea and excess water.
      Method:
      Recall what the kidney removes from the blood and reject reabsorbed substances.
      Examiner tips
      • Kidneys excrete urea, excess water and excess mineral ions.
    25. Question 6(d)

      2 marksOrgan systems in humans
      Step 1: An organ system is a group of organs working together, such as the nervous system and the respiratory (gas exchange) system. Step 2: Other human organ systems include the reproductive, excretory and endocrine systems. Step 3: Chloroplasts and vacuoles are cell parts, haemoglobin and enzymes are molecules, and xylem and phloem are plant tissues, so they are not human organ systems.
      Method:
      Pick two groups of organs that form recognised human systems.
      Examiner tips
      • Human organ systems include nervous, respiratory, reproductive, excretory and endocrine.
    26. Question 7(a)(i)

      1 marksConverting units of plastic size
      Step 1: There are 10 millimetres in 1 centimetre. Step 2: So 0.5 cm = 0.5 × 10 = 5 mm. Step 3: The smallest macroplastic is therefore 5 mm in diameter.
      Method:
      Convert centimetres to millimetres by multiplying by ten.
      Examiner tips
      • 1 cm = 10 mm, so 0.5 cm = 5 mm.
    27. Step 1: The macroplastic mass is zero until 1970 and then increases. Step 2: The microplastic mass increases to a maximum in 2000 and then decreases. Step 3: So macroplastics rise from 1970 onwards while microplastics rise then fall, peaking in 2000.
      Method:
      Take each plastic type separately and describe how its mass changes with time.
      Examiner tips
      • Describe each curve in turn, quoting the years where they start, peak or change.
    28. Step 1: Animals may mistake floating plastic for food and eat it, which can block or damage their gut. Step 2: Animals can also become trapped or tangled in larger pieces of plastic, which can injure or suffocate them. Step 3: Plastic is not a food or a benefit, so the harmful effects are being eaten and trapping animals.
      Method:
      Pick two genuine harmful effects of plastic on marine animals.
      Examiner tips
      • Plastics harm animals by being eaten or by trapping and choking them.
    29. Step 1: Pollution adds harmful substances to water. Step 2: Fertiliser washed off farmland (or untreated sewage) adds nutrients that pollute the water and can cause eutrophication. Step 3: Oxygen from plants, rainwater and sunlight are natural and do not pollute, so the source of pollution is fertiliser.
      Method:
      Choose a man-made input that adds harmful nutrients to the water.
      Examiner tips
      • Fertiliser run-off and untreated sewage are common water pollutants.
    30. Step 1: The characteristics of living organisms are movement, respiration, sensitivity, growth, reproduction, excretion and nutrition. Step 2: Respiration and growth are two of these characteristics. Step 3: Evaporation, condensation, magnification, dilution, filtration and distillation are physical or laboratory processes, not life processes, so the answer is respiration and growth.
      Method:
      List the seven life processes and pick two that are not reproduction.
      Examiner tips
      • MRS GREN: Movement, Respiration, Sensitivity, Growth, Reproduction, Excretion, Nutrition.
    31. Question 8(b)(i)

      1 marksNaming the egg cell
      Step 1: The female gamete (sex cell) is the egg cell, made in the ovary. Step 2: It is released ready to be fertilised by a sperm. Step 3: The sperm is the male gamete, a zygote forms after fertilisation, and an embryo is a later stage, so the female sex cell is the egg cell.
      Method:
      Name the female gamete released before fertilisation.
      Examiner tips
      • The female gamete is the egg cell; the male gamete is the sperm.
    32. Question 8(b)(ii)

      1 marksThe process of fertilisation
      Step 1: Fertilisation is the joining (fusion) of a male gamete nucleus with a female gamete nucleus. Step 2: When a sperm nucleus fuses with an egg nucleus, this is fertilisation. Step 3: Pollination is in flowering plants, germination is a seed growing, and menstruation is loss of the uterus lining, so the process is fertilisation.
      Method:
      Name the fusion of the male and female gamete nuclei.
      Examiner tips
      • Fertilisation = fusion of a sperm nucleus and an egg nucleus.
    33. Question 8(b)(iii)

      1 marksNaming the zygote
      Step 1: When the sperm and egg nuclei fuse, a single cell called the zygote is formed. Step 2: The zygote then divides to form an embryo. Step 3: A gamete is a sex cell before fertilisation, and an embryo and foetus are later stages, so the cell formed straight after fertilisation is the zygote.
      Method:
      Name the single cell produced when the gametes fuse.
      Examiner tips
      • Zygote = the single cell formed at fertilisation, before it divides.
    34. Question 8(b)(iv)

      1 marksImplantation in the uterus
      Step 1: After fertilisation the zygote divides repeatedly as it moves down the oviduct. Step 2: It becomes a hollow ball of cells (stage 4) by the time it reaches the uterus. Step 3: This hollow ball implants (embeds) into the thick uterus lining, so stage 4 is the stage that implants.
      Method:
      Follow the dividing cells to the uterus and pick the stage that embeds in the lining.
      Examiner tips
      • Implantation = the ball of cells embedding into the uterus lining.

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